Two parallelograms of equal area

The area of a parallelogram is p cm^2 and its height is q cm.A second parallelogram has equal area but its base is r cm more than that of the first.Obtain an expression in terms of p,q,r for the height h of the second parallelogram.

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answer

side=

$$l=\frac{p}{q}$$

other side=

$$u=l+r=\frac{p}{q}+r=\frac{p+qr}{q}$$

the other height=

$$\frac{p}{u}=\frac{pq}{p+qr}$$

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