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trigonometry equation

Posted April 18th, 2010 by gokudeep
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i didn't understood this topic please explain it
1.)
$ sinx \ge -\frac{1}{2} $
and the answer is

$ -\frac{\pi}{6}+2n\pi\le x \le \frac{7\pi}{6}+2n\pi $

where n belongs to integers
2.)
similarly for below
$ cosx \ge \frac{1}{2} $
and the answer is
$ 2n\pi-\frac{\pi}{3}\le x \le 2n\pi+\frac{\pi}{3} $

where n belongs to integers
Is there any general methodology for this please help me

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Comments

answer

On April 18th, 2010 Structure says:

You have to look for intervals where green line $ y=-\frac{1}{2} $ is below the graph in red of sine function

You have to look for intervals where green line $ y=\frac{1}{2} $ is below the graph in red of cosine function

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