solving systems of equation by elimination
Posted December 3rd, 2007 by Anonymous
How do I solve this system of equation by elimination...
3x + 6y = -15
6x - 2y = 12
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Answer
We pick to eliminate y.
So we will multiply the second equation by 3 and then we add the two equations.
3x + 6y = -15
6x - 2y = 12
After we multiply the second equation by 3 we get:
3x + 6y = -15
18x - 6y = 36
Add the two equations:
3x+18x=-15+36
21x=21
So
x = 1
We replace x with 1 in 6x - 2y = 12
And we get:
6 - 2y = 12
-2y=12-6
-2y=6
y=-3
So:
x=1 and y=-3