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quadratic equation

Posted June 14th, 2008 by alpha
in

A pole has to be erected at a point on the boundary of a circular park of diameter 13m in such a way that the difference of its distances from 2 diametrically opposite fixed gates A and B on the boundary is 7m.Is it possible to do so?If, yes at what distances from the two gates should the pole be erected?

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Comments

answer

On June 19th, 2008 Structure says:

$ x^2+y^2=169 $
$ x=y+7 $
so $ y^2+14y+49+y^2=169 $
or $ y^2+7y-60=0=(y-5)(y+12)=0 $
$ y=5 $
$ x=12 $

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