Prove that

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answer

$$\frac{cos\theta}{1-sin\theta}=\frac{\sin(\frac{\pi}{2}+\theta)}{1+\cos(\frac{\pi}{2}+\theta)}=\frac{2\sin(\frac{\pi}{4}+\frac{\theta}{2})\cos(\frac{\pi}{4}+\frac{\theta}{2})}{2\cos^2(\frac{\pi}{4}+\frac{\theta}{2})}=tan(\frac{\pi}{4}+\frac{\theta}{2})$$

~~THANK YOU ~~

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``Old theorems never die; they turn into definitions.''
----E. Hewitt

''ALPHA" =)

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