Prove that

Posted May 27th, 2009 by alpha

If a,b, c are in A.P
Then prove that $a^3+4b^3+c^3$ = $3b(a^2+c^2)$

Comments

On May 28th, 2009 Structure says:

$a-b=b-c$

$(a-b)^3=(b-c)^3$

$a^3-3a^2b+3ab^2-b^3=b^3-3b^2c+3bc^2-c^3$

$a^3-2b^3+c^3+3b^2(a+c)=3b(a^2+c^2)$

$a^3-2b^3+c^3+3b^22b=3b(a^2+c^2)$

$a^3+4b^3+c^3+=3b(a^2+c^2)$

On May 28th, 2009 alpha says:

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