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Posted January 12th, 2008 by nikimiki
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The internal measurements of a box are 10cm long, 8cm wideand 7cm high.How many cubes of side 2cm can be put into this box?

‹ Mensuration of the volume of a cube A parallelogram and the intersection of the diagonals ›

Comments

answer

On January 12th, 2008 Isoscel says:

The number is the product of

$$[\frac{10}{2}][\frac{8}{2}][\frac{7}{2}]=5*4*3=60$$

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