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Make t as the subject of the following expression

Posted January 19th, 2008 by nikimiki
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Make t as the subject of the following expression

$$c=\frac{ 1-t^2}{1+t^2 }$$
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answer

On January 19th, 2008 Structure says:
$$c=\frac{ 1-t^2}{1+t^2 }$$
$$c+ct^2=1-t^2$$
$$t^2(c+1)=1-c$$
$$t^2=\frac{1-c}{1+c}$$
$$t=\pm\sqrt{\frac{1-c}{1+c}}$$

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