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Logarithm

Posted June 14th, 2009 by alpha
in

Compute:$ log_6 16 $if $ log_{12} 27 =a $

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answer

On June 14th, 2009 Structure says:
$$log_{12}27=3log_{12}3=3\frac{1}{log_{3}12}=\frac{3}{1+2\log_{3}2}=a$$
$$log_{2}3=\frac{2a}{3-a}$$
$$log_{6}16=4log_{6}2=\frac{4}{log_{2}6}=\frac{4}{1+log_{2}3}=\frac{4(3-a)}{3+a}$$

~~THANK YOU ~~

On June 15th, 2009 alpha says:

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