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Logarithm

Posted June 13th, 2009 by alpha
in

Find the value of :
$ 8^{log _2 \sqrt[3]{121}+\frac{1}{3} $

[It is 8 to the power log of {(121)^1/3+1/3} to the base 2]

‹ Logarithm Quadratic equation ›

Comments

Properties of Logarithm

On June 13th, 2009 alpha says:

$ a^(log_a n )=n $
I used the above property while solving :
$ 2^[3(log_2\sqrt[3]{121}+\frac{1}{3}] $
[2 to the power 3(log ({121}^1/3+1/3) to the base 2 ]
$ a^(log_a n )=n $- by using this property
$ (\sqrt[3]{121}+\frac{1}{3})^3 $

But the answer is 242.

````Maths````
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(((())))
///

answer

On June 13th, 2009 Structure says:
$$8^{log _2 \sqrt[3]{121}+\frac{1}{3}} =8^{\frac{1}{3}+log _2 \sqrt[3]{121}}=8^{\frac{1}{3}}8^{log _2 \sqrt[3]{121}}=2*121=242$$

~~THANK YOU ~~

On June 13th, 2009 alpha says:

````Maths````
000
(((())))
///

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