Logarithm

Posted June 17th, 2009 by alpha

if x, $y\in R$ ,then solve the equations:
$(3y^2+1)log_3 x =1$ , $x^{2y^2+10 }=27$ {It is x^(2y^2+10 )}

$(2y^2+10)log_3 x =3$

$2y^2+10=9y^2+3$

$y^2=1$

$log_3 x =\frac{1}{4}$

$x=3^{\frac{1}{4}}=\sqrt[4]3$

Comments

On June 18th, 2009 alpha says:

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``Old theorems never die; they turn into definitions.''
----E. Hewitt

''ALPHA" =)