Logarithm

if x,$ y\in R $ ,then solve the equations:
$ (3y^2+1)log_3 x =1 $ , $ x^{2y^2+10 }=27 $ {It is x^(2y^2+10 )}

$$(2y^2+10)log_3 x =3$$
$$2y^2+10=9y^2+3$$
$$y^2=1$$
$$log_3 x =\frac{1}{4}$$
$$x=3^{\frac{1}{4}}=\sqrt[4]3$$

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