linear equation in two variables
Posted April 10th, 2008 by alpha
A train covered a certain distance at a uniform speed.If the train would have been 10km/hr faster, it would have taken 2 hours less than the scheduled time.And if the train were slower by 10km/hr ; it would have taken 3 hours more than the scheduled time . Find the distance covered by the train.
Comments
answer
vt=(v-10)(t+3)=vt-10t+3v-30
vt=(v+10)(t-2)=vt+10t-2v-20
v-50=0
v=50km/h
5t=v+10=60
t=12h
Distance=12h*50km/h=10h*60km/h=15h*40km/h=600km