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Limits

Posted December 13th, 2009 by alpha
in

Find:$ \mathop{\lim}\limits_{n \to \infty}nsin(\frac{\pi}{4n})cos(\frac{\pi}{4n}) $

‹ Limits second derivative ›

Comments

general procedure needed?

On December 13th, 2009 alpha says:

How are these types of questions of limits stating 'something tends to infinity' solved?
Is there any defined procedure for solving it?
$ :-? $
-------------------x----------------------------
``Old theorems never die; they turn into definitions.''
----E. Hewitt

''ALPHA" =)

answer

On December 13th, 2009 Structure says:

If $ n\to \infty $ then $ x_n=\frac{1}{n}\to 0 $
Then you can use limits of function.

$$\lim_{x\to 0}\frac{\sin x }{x}=1$$

then

$$\lim_{n\to \infty}\frac{\sin\frac{1}{n}}{\frac{1}{n}}=1$$

Thanks for

On December 15th, 2009 alpha says:

Thanks for answering.

-------------------x----------------------------
``Old theorems never die; they turn into definitions.''
----E. Hewitt

''ALPHA" =)

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