laplace of [( sin(wt)-cos(wt) )^2 ]

Posted October 29th, 2009 by tonees

Anyone knows how to solve

$\mathcal{ L }[( \sin(wt)-\cos(wt) )^2 ](s)$

?
Thanks!

Comments

On October 29th, 2009 Structure says:

$\mathcal{L}(\sin \omega t \:h(t))(s)=\frac{\omega}{s^2+\omega^2}$

$\mathcal{L}((\cos \omega t -\sin \omega t)^2 \:h(t))(s)=\mathcal{L}((1-\sin 2\omega t) \:h(t))(s)=\frac{1}{s}-\frac{2\omega}{s^2+4\omega^2}$

On October 29th, 2009 Structure says:

$\mathcal{L}(\sin \omega t \:h(t))(s)=\frac{\omega}{s^2+\omega^2}$

$\mathcal{L}((\cos \omega t -\sin \omega t)^2 \:h(t))(s)=\mathcal{L}((1-\sin 2\omega t) \:h(t))(s)=\frac{1}{s}-\frac{2\omega}{s^2+4\omega^2}$