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Posted January 21st, 2010 by alpha
in

$ \int \frac{cos^3x}{sin^2x+sinx}dx $

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answer

On January 21st, 2010 Structure says:

$ \int \frac{\cos^3x}{\sin^2x+\sin x}dx = \int \frac{(1-\sin^2x)\cos x}{(1+\sin x)\sin x}dx =\int \frac{(1-\sin x)\cos x}{\sin x}dx=\int(\frac{1}{\sin x}-1)\cos x dx=\ln |\sin x|-\sin x+\Mathcal{C} $

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