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Integrate

Posted January 31st, 2010 by alpha
in
$$\int \tan^4x dx=\int( \tan^4x-1+1) dx=\int (\tan^2x-1)(\tan^2x+1) dx+x=\frac{\tan^3x}{3}-\tan x+x+\mathcal{C}$$
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answer

On February 1st, 2010 Structure says:
$$\int \tan^4x dx=\int( \tan^4x-1+1) dx=\int (\tan^2x-1)(\tan^2x+1) dx+x=\frac{\tan^3x}{3}-\tan x+x+\mathcal{C}$$

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