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Posted January 18th, 2010 by alpha
in

$ \int \frac{2x+3}{(x-1)^2} $

‹ Integrate Integrate ›

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answer

On January 19th, 2010 Structure says:

$ \int \frac{2x+3}{(x-1)^2}dx=\int(\frac{2}{x-1}+\frac{5}{(x-1)^2}) dx=2\ln|x-1|-\frac{5}{x-1}+\Mathcal{C} $

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