Height & Distance

The angle of elevation of the top of a tower from a point A south of the tower is $ \alpha $ and from due east of the tower $ \beta $ .If AB=d , show that the height of the tower is $ \frac{d}{\sqrt{cot^2\alpha+cot^2\beta }} $

Do not solve this question ,only draw the figure because from the given information i am unable to draw the figure.Rest, I will try myself first.

Back to top