Find the range of b

If the roots of then equation $ x^3+bx^2+cx-1=0 $form an increasing G.P. , then find the range of 'b'?

Comments

answer

Let be $ q>0 $ the ratio and

$$x_1=\frac{u}{q}$$
$$x_2=u$$
$$x_3=qu$$

Viete relations are

$$x_1+x_2+x_3=-b$$
$$x_1x_2x_3=1$$

so

$$\frac{u}{q}+u+uq=-b$$
$$\frac{u}{q}*u* uq=1$$
$$u^3=1$$

has a single real root $ u=1 $

$$-b=\frac{1}{q}+1+q\ge 3$$
$$b\in (-\infty,-3]$$

I have used

$$q+\frac{1}{q}\ge 2$$

Back to top