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find the length of AC

Posted July 21st, 2008 by magaski
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ABCD is a square .F is the mid point of AB.BE is one third of BC .If the area of triangle FBE=108cm^2,then find the length of AC.

‹ Prove that the tangents are equal A problem related to coordinate geometry. ›

Comments

answer

On July 21st, 2008 Structure says:

AB=6a
FB=3a
BE=2a
area (FBE)=$ 3a^2=108 $
$ a^2=36 $
a=6
$ AC=6a\sqrt 2=36\sqrt 2 cm $

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