Factor or square root equation

Posted May 27th, 2009 by tracyl

I have an equation for the following, can someone please verify if I have the correct answer.

Equation:

$12x^2 = 147$

I used square root formula

Answer x=3.5

Would factoring be better

As far as I got was:

$(4)(3)x^2 = (49)(3)$

Divide both sides by 3:

$4x^2 = 49$

Then Squared both sides to get: 2x = 7
x = 3.5

Comments

On May 28th, 2009 Structure says:

You have to solve a second order equation.

$4x^2-49=(2x-7)(2x+7)=0$

You have two solutions

$x_1=\frac{7}{2}=3.5$

and

$x_2=-\frac{7}{2}=-3.5$

I have used formula

$a^2-b^2=(a-b)(a+b)$