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Circles

Posted April 18th, 2011 by alpha
in

Consider circles C1: $ x^2+y^2=64 $, C2 with radius 10. If C2 lies on y=x and C2 intersects C1 such that the length of common chord is 16, Find center C2.

‹ proof What is the length of the tangent segment from a circle to a common external point. ›

Comments

answer

On April 18th, 2011 Structure says:

AB=8 BF=10 then AF=6

$$F=(\pm 3\sqrt2,\pm 3\sqrt 2)$$

My doubt is still not resolved!

On April 19th, 2011 alpha says:

I drew the figure correctly, but how to find the center of the second circle?
Symmetry by respect to the origin
-------------------x----------------------------
``Old theorems never die; they turn into definitions.''
----E. Hewitt

''ALPHA" =)

stuck at this point!!

On April 18th, 2011 alpha says:

I tried to draw the figure and found some thing unexpected. The common chord of the circles passes through the origin. how to use the given info. to find the answer.

Quick help required!
Thanks in advance!!

-------------------x----------------------------
``Old theorems never die; they turn into definitions.''
----E. Hewitt

''ALPHA" =)

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